A can do a piece of work in 20 days which b alone can do in 12 days. B worked at it for 9 days then a can finish the remeaning work in
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A can do its work in 20 days
B can do its work in 12 days
LCM of work days = total work
L.C.M of 20 and 12 is 60, so total work is 60.
Work done by A in 1 day = 60/20 = 3
Work done by B in 1 day = 60/12 = 5
Work done by B in 9 days is 5 × 9 = 45
So, 45 unit work B has finished and the remaining work is 60 - 45 = 15
Number of days taken by A to finish his 15 units work = 15/3 = 5 days.
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