Question

A can do a piece of work in 20 days while B can do it in 12 days. B worked at it for 9 days. In how many days A alone can finish the remaining work.

Answer 1

Answer:

Step-by-step explanation:

Lets give the piece of a work a nice round number, 100

So the ‘piece of work’ takes 100 units to complete.

If A can do it in 20 days, they are doing 100/20 units of work per day

100/20 = 5.

B can do the 100 units in 12 days

100/12 = 8.33..

If B does 9 days worth of work, that will be 9 * 8.33… = 75 units.

We need to subtract 75 from the original 100 units of work to see how much work is left to do.

100 -75 = 25 units of work.

Given A does 5 units of work a day, we divide 25 by 5 to tell us how many days it will take to finish the remaining work

25/ 5 = 5

Thus it will take 5 days for A to finish the remaining work.

Answer 2

Answer:

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