A can do a piece of work in 20 days while B can do it in 15 days. With the help of C, they finish
the work in 5 days. In what time would C alone do it?
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Answer:
12 days
Step-by-step explanation:
A does in one day 1/20 part of the work.
B in one day does 1/15 part of the work.
A+ B together do in one day 1/20+1/15 part of the work= 7/60 part of the work.
A+B+ C do in one day 1/5 part of the work.
C alone does in one day 1/5–7/60 part of the work=[ 5/60 ]part of the work
Therefore C alone can do the work in 60/5 days= 12 days answer
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