A can do a piece of work in 20 days while b can do the same work in 25 days. both of them together began the work and after 5 days b left. how many days would a take to finish the remaining work
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Work done by A in 1 day = 1/20
Work done by B in 1 day = 1/25
Work done by A + B in 1 day = (1/20 + 1/25) = 9/100
Work done by A + B in 5 days = (5 × 9/100) = 9/20
So work left = 11/20
Time taken by A to finish the remaining work = (11/20 ÷ 1/20) = (11/20 × 20/1) = 11 days.
The required answer is 11days.
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