Math, asked by gyarweenbanu, 3 months ago


A can do a
piece of work in 21 days. B as 75%
more efficient than A. Find the number of days B will
take to do the same work.​

Answers

Answered by 22bhoomiixe
0

Answer:

28 days

Step-by-step explanation:

21 = 75% of days of B

LET DAYS OF B BE k

21 =  \frac{75 }{100}  \times k \ \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  21  \times 100 = 75 \times k \\ 2100 = 75k \\  \  \frac{2100}{75}  = k \\ 28 = k

therefore,it takes 28 days for B eorker

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