A can do a piece of work in 24 days, B in 32 days and C in 64 days. All begin to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. How many days did the work last?
Answers
Answer:
LCM of 24, 32 and 64 is 192. Hence:
A’ s efficiency = 8
B’s efficiency = 6
C’s efficiency = 3.
In 6 days they produce 17×6=102 units. (1)
Also given that C works alone for 6 days. Number of units produced by C in those 6 days=6×3=18 units (2)
Total (1) + (2) = 120.
Balance units 72 done by Band C :Their 1 days production: 9 units. Hence they worked for 8 days for producing the 72 units.(3)
Total days of work: 6 + 8 + 6= 20 days.
Hence the work was completed in 20 days.
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Answer:
LCM of 24, 32 and 64 is 192. Hence:
A’ s efficiency = 8
B’s efficiency = 6
C’s efficiency = 3.
In 6 days they produce 17×6=102 units. (1)
Also given that C works alone for 6 days. Number of units produced by C in those 6 days=6×3=18 units (2)
Total (1) + (2) = 120.
Balance units 72 done by Band C :Their 1 days production: 9 units. Hence they worked for 8 days for producing the 72 units.(3)
Total days of work: 6 + 8 + 6= 20 days.
Hence the work was completed in 20 days.
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Gm divya