Question

A can do a piece of work in 24 days. B is 60% more efficient than A. The
numbers of days B takes to do the same piece of work is​

Answer 1

Answer:

let the work done by A be x

so

x = 24 days

so according to question :-

60% of x = b

60/100*x = 3/5*x = 3x/5 = b's work

now

If x = 24 days

then 3x/5 = 24/x *3x/5 = 72/5 = 14.4 days

so B can do the same work in 14.4 days

hope you understand plz thank my answer

Answer 2

Step-by-step explanation:

If A Takes 24 Days And B Is 60% Efficient So We Will Take 60% From 24 Days.

60/100 × 24

60 × 24/100

1,440/100

14.4 ~ 14

24-14 = 10 Days

B Can Do The Work In 10 Days