Question

A can do a piece of work in 24 days. B is 60% more efficient than A. The number of days B take to do the same piece of work is ---
a) 9.6
b)12
c) 15
d)17
plese give me step by step ans.​

Answer 1

B efficiency = A effect + 60%

$\implies$ 100% +60%

$\implies$160%.

A working time = 24 days.

$24 \times 100\% = x \times 160\% \\ x = \frac{\cancel2 \cancel4 \times \cancel100}{ \cancel16 \cancel0} \\ \\ x = 15.$

B working time = 15 days.✔

Answer 2

$\huge{\underline{\underline {\mathtt{\purple{H}\pink{E}\green{L}\blue{L}\red{O}\orange{✌}}}}}$

Question

A can do a piece of work in 24 days. B is 60% more efficient than A. The number of days B take to do the same piece of work is

Answer :

$\Large\fbox\red{15\: Days}$

Solution

Let the work done by A be x so,

x = 24 days

As per the question , 60% of x = b

$x \times \frac{60}{100}$

$= \frac{3}{5} \times x$ = B's work

Now

If x = 24 days then,

$x\times \frac{3}{5} = \frac{24}{ x} \times x \times \frac{3}{5}$

$= \frac{72}{5} = 14.4$

Therefore, B can do the work in 14.4 days (or) 15days.

Hope it helps uh!!

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