Question

A can do a piece of work in 24 days. If b is 60% more efficient than A , how many days B takes to complete the same work?

Answer 1

Answer:

B will take 15 days to complete the same work.

Step-by-step explanation:

A takes 24 days to complete the work.

B is 60% more efficient than A

Remember:

If a worker is more efficient, he will take less time to complete the same work.

If a worker is more inefficient, he will take more time to complete the same work.

Now, if

B is 60% more efficient than A

=> A is 60% more inefficient than B for the same work

=> A will take 60% more time than B for the same work

Given that

A takes 24 days to complete the work

Let the number of days taken by B = x

=> 24 = 60% more than x

=> 24 = (60% of x) + x

=> 24 = 0.6*x + x

=> 24 = 1.6*x

=> x = (24/1.6)

=> x = 15

B will take 15 days to complete the same work

Alternate Method

A can do the work in 24 days

=> A does (1/24) work in 1 day

If B is 60% more efficient, B can do 60% more work than A in the same time

=> B does [(1/24) + (60% of 1/24)] of the work in 1 day

=> B does {1/24 + 0.6/24] of the work in 1 day

=> B does (1.6/24) of the work in 1 day

=> B takes (24/1.6) days to complete the work

=> B takes 15 days to complete the work

Remember: If a man does (1/n) of the work in 1 days, he will take n days to complete the work.

Answer 2

$\huge\bold\purple{Hola\:User!!}$

Question

A can do a piece of work in 24 days. B is 60% more efficient than A. The number of days B take to do the same piece of work is

Answer:

$\Large\fbox\red{15\: Days\:\:(or)\:\:14.4\:Days}$

Solution

Let the work done by A be x so,

x = 24 days

As per the question , 60% of x = b

$x \times \frac{60}{100}$

$= \frac{3}{5} \times x$ = B's work

Now

If x = 24 days then,

$x\times \frac{3}{5} = \frac{24}{ x} \times x \times \frac{3}{5}$

$= \frac{72}{5} = 14.4$

Therefore, B can do the work in 14.4 days (or) 15days.

Hope it helps uh!!

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