Question

A can do a piece of work in 24 days.if b is 60% more efficient than A, then the number of days required by B to do the twice as large as the earlier work

Answer 1

Answer:

30

Step-by-step explanation:

The total work is 120....

And double the work then it is 240

And divided by b's efficiency.. 8...then you will get ans 30

Answer 2

The number of days required by B to do the twice as large as the earlier work = 30 days

Step-by-step explanation:

Let efficiency of A = 100

Efficiency of B = 160

Ratio of efficiencies of A & B is = 100 : 160 = 5 : 8

No. of days required to finish the work by A & B are in the ratio = 8 : 5

Since no. of days required by A to complete the work = 24 days

So number of days required to complete the work by B = $\frac{24}{8}$ × 5 = 15 days

If the work is doubled then the number of days required to complete the work by B = 15 × 2 = 30 days.