Question

A can do a piece of work in 24 days. If B is 60% more efficient than A how many days are required by B to do the twice as long as the earlier work is.​

Answer 1

Answer:

We know that B is 60% more efficient than A. So, the amount of work done by B in one day can be calculated as follows, Work done by B in 1 day =124+60100×124=10240+6240=16240=115. Therefore, the number of days required by B to complete the same quantity of work as A is 15 days.