Question

A can do a piece of work in 24 days. if B is 60% more efficient than A, then B can complete the work in? ​

Answer 1

Ans.) B completed the work in 15 days.

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Answer 2

B can complete the work in 15 days.

Step-by-step explanation:

It is given that A can do a piece of work in 24 days.

One day work of A = $\frac{1}{24}$

B is 60% more efficient than A.

One day work of B = $\frac{1}{24}+\frac{60}{100}\times \frac{1}{24}$

One day work of B = $\frac{1}{24}+\frac{1}{40}$

One day work of B = $\frac{5+3}{120}$

One day work of B = $\frac{8}{120}$

One day work of B = $\frac{1}{15}$            .... (1)

Let B can complete the work in t days.

One day work of B = $\frac{1}{t}$              .... (2)

From (1) and (2) we get

$\frac{1}{t}=\frac{1}{15}$

$t=15$

Therefore, B can complete the work in 15 days.

#Learn more

A can do a piece of work in 24 days. If b is 60% more efficient than A , how many days B takes to complete the same work?

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