English, asked by motaleb432, 1 year ago

A can do a piece of work in 24 days which B can do in 21 days.They begin together but 3 days before the end of the works A leaves. The total number of days to complete the is?

Answers

Answered by MasterMohammad

HELLO DEA FRIEND. ..

HERE IS UR ANSWER....

A'S 1 DAY WORK IS = 1/24 ...
B'S 1 DAY WORK =1/21
....
A+B 1 DAY WORK =1/24+1/21......
8+7/168

=> 15/168..

A+B 3 DAY WORK 3×15/168

45/56...

now remaining work is 1-45/56
=> 9/56...

Now b can do the remaining work in = 9×21÷56

189÷56= 3-21/56...

HOPE IT VLL HELP UH. ...

THANK YOU. ..

MARK IT AS BRAINLIST ANSWER. ..

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motaleb432: B' s 3 days work=(1/21*3)=1/7

MasterMohammad: mark it as BRAINLIST ANSWER

motaleb432: B's 3 day's work (1/21*3)= 1/7. Remaining work=(1-1/7)=6/7. (A+B)'s 1 days work =(1/14+1/21)= 5/42. Now, 5/42 work is done by (A+B) in 1 day 6/7 work is done by A &B in (42/5*6/7)= 36/5 days . Total time taken=(3+36/5)=10.2 days. Answer: 10.2 days

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