A can do a piece of work in 24 days while B alone can do it in 32 days. if A B and C working together finish it in 8 days In how many days can C alone finish the work
Answers
Answered by
1
Answer:
19.2 days
Step-by-step explanation:
A in 24 days can complete = 1 piece of work
So in 1 day A can complete = 1/24 piece of work
B in 32 days can complete = 1 piece of work
So in 1 day B can complete = 1/32 piece of work
Let C in x days can complete = 1 piece of work
So in 1 day C can complete = 1/x piece of work
Together they can complete the work in 8 days
8[(1/24) + (1/32) + (1/x)] = 1
x = 19.2 days
Similar questions