Question

A can do a piece of work in 24 days while B alone can do it in 16 days .with the helo of C ,they finish the work in 8 days .in how many days can C alone do the work

Answer 1

48 days from 1/24+1/16+1/c=1/8 giving c=48

Answer 2

Answer:

12 hours

Step-by-step explanation:

A can do work in days = 24

A's 1 day work = $\frac{1}{24}$

B can do work in days = 16

B's 1 day work = $\frac{1}{16}$

Let c's 1 day work be $\frac{1}{x}$

With help of C ,they finish the work in 8 days

1 hour work when they work together = $\frac{1}{8}$

So, $\frac{1}{8}=\frac{1}{6}+\frac{1}{24} +\frac{1}{x}$

$x=-12$

Negative sign shows that Pipe C is outlet

So, tap C can empty tank in 12 hours