Question

A can do a piece of work in 24 hours while B alone can do it in 16 hours . if a b and c working together can finish it in 8 hours in how many hours can C alone finish the work ?

Answer 1

c work 48 hrs
answer is 48 hrs

Answer 2

C can do a piece of work in 48 hours.

Step-by-step explanation:

A can do a piece of work in 24 hours.

One hour work of A = $\frac{1}{24}$

B can do a piece of work in 16 hours.

One hour work of B = $\frac{1}{16}$

A, B and C working together can finish it in 8 hours.

One hour work of A, B and C together = $\frac{1}{8}$

Let C can do a piece of work in x hours.

One hour work of C = $\frac{1}{x}$

One hour work of (A + B + C) = One hour work of A, B and C together

$\frac{1}{24}+\frac{1}{16}+\frac{1}{x}=\frac{1}{8}$

$\frac{1}{x}=\frac{1}{8}-\frac{1}{24}-\frac{1}{16}$

$\frac{1}{x}=\frac{6-2-3}{48}$

$\frac{1}{x}=\frac{1}{48}$

After reciprocal we get

$x=48$

Therefore, C can do a piece of work in 48 hours.

#Learn more:

A and b can do a piece of work in 7 days. with the help of c they finish the work in 5 days. c alone can do that piece of work in?

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