Question

A can do a piece of work in 24 hours while B alone can do it in 16 hours. If A, B and C
working together can finish it in 8 hours, in how many hours can C

alone finish the work?

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Answer 1

Answer:

$lcm \: 48 \:( total \: units) \\ a = 2 \: units \: per \: hr \\ b = 3 \: units \: per \: hr \\ a + b + c = 6 \: units \: per \: hr \\ (a + b + c ) - (a + b) = 6 - 5 = 1 \\ 48 \div 1 = 48hours$

Answer 2

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