Math, asked by kristi85, 1 year ago

a can do a piece of work in 24 hours while B alone can do it in 16 hours if a b and c working together can finish it in 8 hour in how many hours can see alone finish the work

Answers

Answered by lakshyajindal0310
112

Answer:

48 days

Step-by-step explanation:

piece of work done by A in one hour = 1/24

piece of work done by B in one hour = 1/16

piece of work done by A and B together in one hour= 1/24 +1/16

                                                                      = 5/48

piece of work done by A ,B and C together in one hour = 1/8


piece of work done by C in one hour= 1/8 - 5/48

                                                               = 1/48

Days taken by C to complete the work = 1/(1/48)

                                                                 = 48 days          



kristi85: thanks
Answered by vikrantsihag123
15

Answer:

48

Step-by-step explanation:

please make me a perfect answer man

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