Math, asked by mitalirathore7201, 1 month ago

A can do a piece of work in 24 hours while b can do a piece of work 16 hours if a b c working together in 8 hours in how many c alone can do the work

Answers

Answered by devpichy
2

Answer:

C can alone do the work in 48 hours

Step-by-step explanation:

A's one hour work = 1/24

B's one hour work = 1/16

Let C's one hour work be 1/c

So, if all work together, the work will be completed in = 8 hours

if all work together, work completed in 1 hour = 1/8

Now,

A's one hour work + B's one hour work + C's one hour work = Everyone's one hour work

⇒ 1/24 + 1/16 + 1/c = 1/8

⇒ 1/c = 1/8 - 5/48

⇒ 1/c = 1/48

⇒ C's whole work done alone in = 48 hours

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