Question

A Can do
a piece of work in 25 days
and b alone can do it
in
20 days and both work
together for 5 days
then A leaves on ,
how many
days does
takes the
B?​

Answer 1

Answer:

In 1- day A and B can do= 1/20+ 1/25 = 9/100.

In 5- days both can do= 9/100 x 5 =45/100.

Number days required by A to finish the remaining work= (55/100)÷(1/20) = 11- days.

========================== Another method A does the work till the end and B does the work for 5- days only.

If the total work if finished in X- days, then

So X/20 + 5/25= 1

5X+ 20= 100

X= 80/5= 16.

So complete work is done in 16- days.

A alone does after B- left= 16–5= 11- days.

If you are satisfied with my answer then mark me as brainliest.