Question

A can do a piece of work in 25 days and b can do it in 20 days. they work together for 5 days and then a quits. b completes the remaining work. if they are paid rs. 750 for the job, find b's share ?

Answer 1

Answer: B's share = Rs. 581.25

Step-by-step explanation:

Given :

A can do a piece of work in 25 days.

B can do a piece of work in 20 days.

Rs. 750 is paid for completing the job.

Solution :

∴ Work done by A in 1 day = $\frac{1}{25}$

∴ Work done by B in 1 day = $\frac{1}{20}$

∴ Work done by them together in 1 day= $\frac{1}{25} + \frac{1}{20}$ = $\frac{9}{100}$

∴ Work will be completed by both A and B in 100/9 days.

⇒ Work done together in 5 days = $\frac{9 * 5}{100} = \frac{9}{20}$

∴ Work left = $1 - \frac{9}{20} = \frac{11}{20}$

∴ Work done by A = $\frac{9}{40}$

∴ Work done by B = $\frac{11}{20} + \frac{9}{40} = \frac{22 + 9}{40} = \frac{31}{40}$

∴ A's share = $\frac{9*750}{40} = Rs. 168.75$

∴ B's share = $\frac{31 * 750}{40} = 581.25$

#SPJ2