A can do a piece of work in 25 days and B can finish it in 20 days. They work together for 5 days and then A leaves. In how many days will B finish the remaining work?
Answers
Answer:
11 days
Step-by-step explanation:
A can do a piece of work in 25 days
Work done by A in one day = 1 / 25
B can finish it in 20 days
Work done by B in one day = 1 / 20
A and B started working together
Work done by A and B in one day = 1 / 25 + 1 / 20 = ( 4 + 5 ) / 100 = 9 / 100
A and B work together for 5 days
Work done by A and B in 5 days = 5 × ( 9 / 100 ) = 9 / 20
A leaves after 5 days. So Remaining work is to be done by B
Remaining work done by B = 1 - 9 / 20 = ( 20 - 9 ) / 20 = 11 / 20
11 / 20 work done by B in = ( 11 / 20 ) × 20 = 11
Hence B will finish the remaining work in 11 days.
Given :
- Number of days A work = 25 days
- Number of days B work = 20 days
- Number of days A & B both work =5days
To Find :
- Number of days B will finish the remaining work
Solution :
▪️Work done by A in 1 day = 1/25
▪️Same Work done by B in 1 day = 1/20
Then,
Total work done by A & B in one day =1/25+1/20
= 45/500
= 9/100
When A & B together work for 5 days, work done will be;
Total work done by A & B in 5 days =5×9/100
= 9/20
Now,
After 5 days when, A leaves the remaining work done by B will be;
Remaining work done by B = 1 - 9/20
= 11 /20
Hence, number of days remaining work done by B = 11×20/20 = 11 days