A can do a piece of work in 25 days and B Can finish it in 20 days They work together for 5 days and then A goes away In hw many days will B finish the remaining work solve full answer
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Answered by
1
A, work is1/25
B,work is1/201
A+B,work is1/25+1/20,9/100,work is9/100
A+B work for 5 days ,his work is5×9/100=9/20
remaining work is 1-9/20=20-9/20,11/20
B ,1/20 in 1days
11/20work in11/20×20=11 days
B,work is1/201
A+B,work is1/25+1/20,9/100,work is9/100
A+B work for 5 days ,his work is5×9/100=9/20
remaining work is 1-9/20=20-9/20,11/20
B ,1/20 in 1days
11/20work in11/20×20=11 days
Answered by
3
Work of A in one day=1/25
Work of B in one day=1/20
Work of (A+B) in one day=1/25+1/20
=5+4/100
=9/100
Work of (A+B) in5 days=9/100*5
=9/20
Remaining work=1-9/20
=11/20
B complete the work=11/20÷1/20
=11/20*20
=11 days.
Thank you
Work of B in one day=1/20
Work of (A+B) in one day=1/25+1/20
=5+4/100
=9/100
Work of (A+B) in5 days=9/100*5
=9/20
Remaining work=1-9/20
=11/20
B complete the work=11/20÷1/20
=11/20*20
=11 days.
Thank you
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