A can do a piece of work in 25 days and B can finish it in 20 days. They work together for 5 days then A leaves. In how many days will B finish the remaining work?
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Answer:
Step-by-step explanation:
per day A does 1/25 of the total work while B does 1/20th of the total work.
Together they do 1/25 + 1/20 =9/100 th work in 1 day
They work for 5 days so they have completed (9/100)*5 =9/20 of the total work
Let the total work be 1, so the remaining work is 1 - (9/20) = 11/20
Since B completes 1/20th work in day, he will need x days for completion of 11/20 th work
so (1/20)*x = 11/20
so x = (11*20)/20
x = 11 days
Answer: B requires 11 days to complete the remaining work
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