Math, asked by aliahlily, 1 day ago

A can do a piece of work in 25 days and B can finish it in 20 days. They work together for five days and then A goes away. In how many days will B finish the remaining work.​

Answers

Answered by ADITYABHAIYT
9

A's 1 day's work = 1/25

Similarly, B's 1 day's work = 1/20

A's and B's together 1 day's work

=> 1/25 + 1/20 = 4/100 + 5/100 4+5/100

= 9/100

Their 5 day's work together = 5 x 1 day's work

1 - 45/100 = 100/100 - 45/100=100-45/100

= 55/100

Now, this remaining work is done by B.

Now, this remaining work is done by B.Let B takes x days to complete it.

1/20 * x = 55/100

=> x = 55/100*20

=> x = 55/5

=> x = 11 (ans)

Hence, B will finish the remaining work in 11 days.

Answered by vikassail36
2

11 days

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