Question

A can do a piece of work in 25 days and B can finish it in 20 days.Both started the work together. After 5 days, A left. In how many days will B finish the remaining work

Answer 1

Answer:

11 days

Step-by-step explanation:

in 1 day they can do = 1/25 + 1/20

= (4+5)/100

= 9/100 of the work

in 5 days they can do = 9/100 * 5

= 9/20 of the work

remaining work = 1 - (9/20)

= 11/20

B can do (11/20) of the work in = 11/20 * 20

= 11 days

Answer 2

A in one day = 1/25
in 5 days = 5/25
= 1/5

in 5 days B = 1/4

Today work in 5 days = 1/5 + 1/4
= 9/20

Remaining work = 11/20

Now, B will take = 11/20 x 20 = 11 days