A can do a piece of work in 25 days and B can finish the same 20 days .They wirked together for 5 daya and A leave In how many day B finish the remaining work
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Answer:
11 days
Step-by-step explanation:
Total work = LCM of 25 and 20 = 100
Efficiency of A = 4
Efficiency of B = 5
Combined efficiency = 9
They worked together for 5 days; work completed = 9x5= 45
Remaining work = 100 - 45 = 55
B will complete the remaining work in 55/5 = 11 days
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