A can do a piece of work in 25 days and B can finish the same work in 20 days. They worked togetjer for 5 days and then A leaves. B alone will finish the remaining work in
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Answer:
11 days
Step-by-step explanation:
A =25
B= 20
so total work =lcm of A,B=100
A's 1 day work=100/25=4
B's one day work=100/20=5
Both togather 5days work=(5+4)*5=45
remaining work=100-45=55
so B will complete it in 55/5=11.
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