Math, asked by saigoutami11, 6 months ago

A can do a piece of work in 25 days, which B alone can do im 20 days. A started tge work and was joined by B after 10 days. The work lasted for
(a) 12 whole 1/2 days (b) 16 whole 2/3 days (c) 7 days (d)14 days​

Answers

Answered by abhinav2618
1

Answer:

Work done by A in l0 days = (1/25) *10 = 2/5

Remaining work = 1 - (2/5) = 3/5

(A+B)s 1 days work = (1/25) + (1/20) = 9/100

9/100 work is done by them in 1 day.

hence 3/5 work will be done by them in (3/5)*(100/9)

= 20/3days.

Total time taken = (10 + 20/3) = 16*(2/3) days

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