Math, asked by abhimanyukr462, 1 year ago

A can do a piece of work in 25 days, which B alone can do in 12 days. B worked as it for 9 days. A can finish the remaining work in how many days?

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Answered by Anonymous
1

A & B together can complete work in (25x20)/(25+20) =500/45 = 100/9 days. They complete 5 x 9/100= 9/20 work in 5 days. Remaining 11/20 work done by B in 11/20 x 20 = 11 days. A works only for 5 days completing 5/25 = 1/5 part of work.

Answered by Anonymous
1

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