A can do a piece of work in 30 days and B can do it in 20 days. They work together for 4 days and then B leaves the job. In how many days, will A finish the remaining work?
Answers
Given :- A can do a piece of work in 30 days and B can do it in 20 days. They work together for 4 days and then B leaves the job.
To Find :- They work together for 4 days and then B leaves the job. ?
Solution :-
→ LCM of 30 and 20 = 60 units = Let total work .
so,
→ Efficiency of A = Total work / Time taken = 60/30 = 2 units / day .
and,
→ Efficiency of B = Total work / Time taken = 60/20 = 3 units / day .
then,
→ Work done by (A + B) in one day = (2 + 3) = 5 units .
so,
→ Work done by (A + B) in first 4 days = 5 * 4 = 20 units .
Now,
→ Work left to be done = 60 - 20 = 40 units .
since B left, only A has to complete left work .
therefore,
→ Time taken by A to complete the remaining work = Lefy work / Efficiency of A = 40/2 = 20 days (Ans.)
Hence, A will finish the remaining work in 20 days .
Learn more :-
Giri does 2/5 piece of work in 10 days. Ankit does 5/9 of the remaining work in 15 days and Gaurav finishes remaining wo...
https://brainly.in/question/21025557
Shivam alone can do a work in 12 days and Maanik alone can do it in, 15 days. Both started the work together and after w...
https://brainly.in/question/14687371
Answer:
23.75
Step-by-step explanation:
a + b = (1/30)+(1/20)
= (20+30)/60
= 50/60
= 5/6
(a+b) 's 4 days work = (1/4)*(5/6)
= 5/24
Remaining work = 1-(5/24)
= 19/24
A's remaining work = (19/24)*30
= 95/4
= 23.75