Math, asked by harshraj555555, 1 month ago

A can do a piece of work in 30 days and B can do it in 20 days. They work together for 4 days and then B leaves the job. In how many days, will A finish the remaining work?​

Answers

Answered by RvChaudharY50
6

Given :- A can do a piece of work in 30 days and B can do it in 20 days. They work together for 4 days and then B leaves the job.

To Find :- They work together for 4 days and then B leaves the job. ?

Solution :-

→ LCM of 30 and 20 = 60 units = Let total work .

so,

→ Efficiency of A = Total work / Time taken = 60/30 = 2 units / day .

and,

→ Efficiency of B = Total work / Time taken = 60/20 = 3 units / day .

then,

→ Work done by (A + B) in one day = (2 + 3) = 5 units .

so,

→ Work done by (A + B) in first 4 days = 5 * 4 = 20 units .

Now,

→ Work left to be done = 60 - 20 = 40 units .

since B left, only A has to complete left work .

therefore,

→ Time taken by A to complete the remaining work = Lefy work / Efficiency of A = 40/2 = 20 days (Ans.)

Hence, A will finish the remaining work in 20 days .

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Answered by DeepikaPolisetty
3

Answer:

23.75

Step-by-step explanation:

a + b = (1/30)+(1/20)

= (20+30)/60

= 50/60

= 5/6

(a+b) 's 4 days work = (1/4)*(5/6)

= 5/24

Remaining work = 1-(5/24)

= 19/24

A's remaining work = (19/24)*30

= 95/4

= 23.75

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