A can do a piece of work in 30 days and b can finish it in 25 days. they work together for 10 days and then a leaves. in how many days will b finish the remaining work?
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Answer:
11 days
Step-by-step explanation:
Let the TOTAL WORK = LCM (20, 25) = 100 parts
Note: We take total work as LCM of the time taken for convenience of calculation.
•A takes 25 days => A does 4parts/day
•B takes 20 days => B does 5parts/day
•(A+B) together do 9parts/day
•In 5 days, work completed together = 45 parts
•Remaining work = 55 parts
•Now, A has left so remaining work will be done by B
•Time Taken =55/5 =11
So, Time taken by B to complete the remaining work =11 days
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