A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ?
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Thanks for A2A.
Now, A can do a piece of work in 80 days. So, let the TOTAL WORK = 80 units.
A -> 80 days = 1 unit/day
So, in 10 days, A has completed 10 units.
Remaining Work = 70 units.
Now, B finishes this in 42 days. So rate of work if B =70427042 =5353unit/day
Thus, A + B =1+531+53 = 8383
So, TIME TAKEN = 80838083 = 30 Days (Answer)
Now, A can do a piece of work in 80 days. So, let the TOTAL WORK = 80 units.
A -> 80 days = 1 unit/day
So, in 10 days, A has completed 10 units.
Remaining Work = 70 units.
Now, B finishes this in 42 days. So rate of work if B =70427042 =5353unit/day
Thus, A + B =1+531+53 = 8383
So, TIME TAKEN = 80838083 = 30 Days (Answer)
Answered by
0
A's per day work= 1/30 B complete remaining work in 20 days,
work done by a in days=(1/30)6=1/5remaining
work= 5/6 done by B in 20 days then B's per day work=(5/6)(1/18)=1/24
work will completed both A & B working together is inverse of (1/30)+(1/24)=40/3
work done by a in days=(1/30)6=1/5remaining
work= 5/6 done by B in 20 days then B's per day work=(5/6)(1/18)=1/24
work will completed both A & B working together is inverse of (1/30)+(1/24)=40/3
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