A can do a piece of work in 30 days while B can do it in
40 days. In how many days can A and B working together do it.
Answers
Answered by
0
Answer:
120/7 days
Step-by-step explanation:
A-30
B-40
L. C. M of 30 and 40 is 120
Capacity of A - 4
Capacity of B - 3
Together capacity of A and B = 3+4 = 7
Total work = 120
Total capacity = 7
Than put the value = work / time
= 120/7 Days
Answered by
2
A piece of work can be done by
A in = 30 days
B in = 40 days
Work done by
A in one day = 1/30
B in one day = 1/40
Now when both work together then , work done by both of them in one day is
1/30 + 1/40 = 4/120+3/120 = 7/120
This means
The work done would be completed by them in
120 / 7 days = 17 1/7 days
A in = 30 days
B in = 40 days
Work done by
A in one day = 1/30
B in one day = 1/40
Now when both work together then , work done by both of them in one day is
1/30 + 1/40 = 4/120+3/120 = 7/120
This means
The work done would be completed by them in
120 / 7 days = 17 1/7 days
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