a can do a piece of work in 4 days. b can do it in 5 days. with the assistance of c they completed the work in 2 days. find in how many days can c alone do it? 20 30 25 18 next ques
Answers
Answered by
18
20 will be the answer
Answered by
33
in this problem we solve very easy method
by using lcm method
A = 4
B = 5
lcm of , 4 , 5 = 20 unit
suppose 20 unit is total work
A and B separate do one days work is
20/4 = 5 unit
and
20/5 = 4 unit
sum = 5 + 4 = 9 unit together one days
in two days.
9 × 2 = 18 unit
remaining work = 20 - 18 = 2 unit
it can do C in 2 day's
means 1 days = 1 unit
total work ÷ 1
20/1 = 20 days
Ans = 20 days of C
by using lcm method
A = 4
B = 5
lcm of , 4 , 5 = 20 unit
suppose 20 unit is total work
A and B separate do one days work is
20/4 = 5 unit
and
20/5 = 4 unit
sum = 5 + 4 = 9 unit together one days
in two days.
9 × 2 = 18 unit
remaining work = 20 - 18 = 2 unit
it can do C in 2 day's
means 1 days = 1 unit
total work ÷ 1
20/1 = 20 days
Ans = 20 days of C
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