A can do a piece of work in 4 days B can do it in 5 days and c can do it in 10days. then a b c together can do the work in how many days
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Work done by A in 1 day = 1/4
Work done by B in 1 day = 1/5
Work done by C in 1 day = 1/10
Work done by ( A+B+C ) i.e., by all of them together in 1 day = ( 1/4 + 1/5 + 1/10 ) = 11/20
Therefore ( A+B+C ) can finish the work in 20/11 days = 1 whole 9/11 days.
Hope this helps you friend......
Be brainly ☺️☺️☺️
sivaprasath:
20/11 days = 1 whole 9/ 20 days (or) 1 whole 9/11 days ??
oops sorry my mistake
Tq ....
I have posted one image also. can u plz solve those problems ??
um I already answered...sorry
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