A can do a piece of work in 4 days, b can do the same work in 8 days and c can do the same work in 12 days. a work on day1, b work on day 2, c works on day 3 and so on then in how many days the work will be completed
Answers
Answered by
1
A's one day work= 1/4
B's one day work= 1/8
C's one day work= 1/12
3 day work= 1/4+1/8+1/12
= 6+3+2/24= 11/24
6 day work = 11x2/24= 22/24
total work = 1
remaining work= 1-22/24= 24-22/24= 2/24= 1/12
on 7th day A's turn = 1/12-1/4= 1-3/12= -2/12(no remaining work)
that means on 7th day work will be completed by A.
B's one day work= 1/8
C's one day work= 1/12
3 day work= 1/4+1/8+1/12
= 6+3+2/24= 11/24
6 day work = 11x2/24= 22/24
total work = 1
remaining work= 1-22/24= 24-22/24= 2/24= 1/12
on 7th day A's turn = 1/12-1/4= 1-3/12= -2/12(no remaining work)
that means on 7th day work will be completed by A.
Similar questions