Math, asked by nandarawat441983, 4 months ago

A can do a piece of work in 4 days, B in 3 days. A,B and C together cab do it in 3/2 days. How lobmng wilk C working alone take to do the work?​

Answers

Answered by Anonymous
3

A and B can do a piece of work in 3 days, means that A and B do 1/3rd the work in a day.

A and B can do a piece of work in 3 days, means that A and B do 1/3rd the work in a day.B and C can do the same piece of work in 4 days, means that B and C do 1/4th the work in a day.

A and B can do a piece of work in 3 days, means that A and B do 1/3rd the work in

A and B can do a piece of work in 3 days, means that A and B do 1/3rd the work in a day.B and C can do the same piece of work in 4 days, means that B and C do 1/4th the work in a day.C and A can do the same piece of work in 4 days, means that C and A do 1/4th the work in a day.

So (A+B)+(B+C)+(C+A) or 2(A+B+C) can do (1/3)+(1/4)+(1/4) = (4+3+3)/12 or 10/12th of the work in a day, or A+B+C can do 5/12th of the work in a day. So C along can do 5/12–1/3 or 5/12–4/12 = 1/12th of the wok in a day. So C will take 12 days to do the same job, working alone.

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Answered by ranikhangare
1

Answer:

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