A.can do a piece of work in 40 days &B .can do the same work in 60 days . working together,in how many days will they complete the work?
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Answered by
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Answer is 30.67 days.
Solution:
A's 1 day work = 1/60
B's 1 day work = 1/40
Together they can finish in = 1/60 + 1/40 = 1/24
Therefore, together they take 24 days to complete the work.
Now, if A left 10 days before completion then,
Number of days A & B worked together = 24-10 = 14 days.
Percent completion of both A & B working together for 14 days is,
(1/24) × 14 × 100 = 58.33%
B's 1 day efficiency = 1/40 ×100 = 2.5%
& the left work is = 100 - 58.33 = 41.67%
Therefore, no. of days further B will take to complete the work is,
41.67/2.5 = 16.67 days
Therefore, the work finished at 14+16.67 = 30.67 days.
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Answered by
1
1/60 + 1/40 = 1/24
1/60 = A’s work in 1 day
1/40 = B’s work in 1 day
1/60 = A’s work in 1 day
1/40 = B’s work in 1 day
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