Question

A can do a piece of work in 40 days; b can do the same in 30 days. A started alone but left the work after 10 days, then b worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in

Answer 1

C can complete the work alone in 24 days .

Let the total work be x units.

A can do the work in 40 days .

1 day work of A = x/40

B can do the work in 30 days .

1 day work of B = x/30

For the first 10 days A does the work alone.

10 days work of A = 10 × x/40 = x/4

For the next 10 days B does the work alone.

10 days work of B = x/3

C does the remaining work left in the last 10 days .

x = 10 days work of C + x/3 + x/4

=> 10 days work of C = 5x/12

C can do 5x/12 units of work in 10 days.

C can do x units of work in = (x × 10)/(5x/12)

= 24 days