Question

A can do a piece of work in 40 days . He finishes his work in 8 days. B finishes his work in 16 days . How long will take to complete the work together?​

Answer 1

Answer:

Step-by-step explanation: sorry I don't know the answer

I read in class 1

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Answer 2

Answer:

$\underline{\bigstar\:\textsf{B can do work in :}}$

$:\implies\tt \dfrac{Time_1}{A}+\dfrac{Time_2}{B}=Work\\\\\\:\implies\tt \dfrac{8}{40} + \dfrac{16}{B} = 1\\\\\\:\implies\tt \dfrac{1}{5} + \dfrac{16}{B} = 1\\\\\\:\implies\tt \dfrac{16}{B} =1 - \dfrac{1}{5}\\\\\\:\implies\tt \dfrac{16}{B} = \dfrac{4}{5}\\\\\\:\implies\tt B = \dfrac{16 \times 5}{4}\\\\\\:\implies\tt B =4 \times 5\\\\\\:\implies\tt B = 20 \:Days$

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$\underline{\bigstar\:\textsf{(A + B) can do work in :}}$

$\dashrightarrow\tt\:\:(A+B)=\dfrac{A \times B}{A + B}\\\\\\\dashrightarrow\tt\:\:(A+B) = \dfrac{40 \times 20}{40 + 20}\\\\\\\dashrightarrow\tt\:\:(A+B) = \dfrac{40 \times 20}{20 \times 4}\\\\\\\dashrightarrow\:\:\underline{\boxed{\tt(A+B) = 10 \:Days}}$

⠀

$\therefore\:\underline{\textsf{They'll together complete work in \textbf{10 Days}}.}$