A can do a piece of work in 40 days. he starts working, but having some other engagements he drops out after 5 days. thereafter, b completes this work in 21 days. how many days would a and b take to complete this work working together?
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Explanation:
(A+C) in x days so B completes in 3x days
then (1/x) + (1/3x) = 1/10
solve, x = 40/3
so B in 3x = 3*(40/3)= 40 days
OR
Given A+B+C = 10 and that B takes 3 times as A+C, so A+C is three times stronger than B
So this means that 4 times stronger can do work in 10 days
So 1 time stronger(B) in 4*10 = 40 days
(A+C) in x days so B completes in 3x days
then (1/x) + (1/3x) = 1/10
solve, x = 40/3
so B in 3x = 3*(40/3)= 40 days
OR
Given A+B+C = 10 and that B takes 3 times as A+C, so A+C is three times stronger than B
So this means that 4 times stronger can do work in 10 days
So 1 time stronger(B) in 4*10 = 40 days
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