A can do a piece of work in 40 days he work for it 5 days and then be alone how many could both do it
Answers
Answered by
0
Answer:
the answer is
Step-by-step explanation:
A csn do a piece of work in 40 days
Work of A in 1 day=1/40
Work of A in 5 days=5/40=1/8
1/8th part of work is done by A
Remaining work=(1−81)=87
7/8th part is done by B in 21 days
Total work will be done by B in =8721=721×8=24days
Work done by B in one day=1/24
Work done by A and B together in one day will be(401+241)
(1203+5)=1208=151
A and B will take 15 days to complete the work together
Answered by
0
Step-by-step explanation:
hope helps you
please mark me as brainliest answer
Attachments:
Similar questions