A can do a piece of work in 40 days. He works at it for 8 days and the B finished the remaining work in 16 days. How long will they take to complete the work if they do it together?
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Answer:
A csn do a piece of work in 40 days
Work of A in 1 day=1/40
Work of A in 5 days=5/40=1/8
1/8th part of work is done by A
Remaining work=(1−
8
1
)=
8
7
7/8th part is done by B in 21 days
Total work will be done by B in =
8
7
21
=
7
21
×8=24days
Work done by B in one day=1/24
Work done by A and B together in one day will be(
40
1
+
24
1
)
(
120
3+5
)=
120
8
=
15
1
A and B will take 15 days to complete the work together
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