A can do a piece of work in 40 days. He works at it for 8 days and then B finishest
remaining work in 16 days. How long will they take to complete the work if they
it together?
Answers
Answer:
Here is a simple method for solving such problems where the amount of work is not given. Generally we assume the work to be 1 unit.
Now this time, let's assume the work is of eating chocolates.
Assume the total number of chocolates be 80 (L.C.M of 40, 8, 16)
Condition 1: X eats 80 chocolates in 40 days.
Hence efficiency of X is : 2 chocos / day
Condition 2: X work for 8 days. Then Y work for 16 days
The number of chocolates eaten by X in 8 days : 2*8 = 16
Rest of the chocolates are eaten by Y in 16 days.
Chocolates left= 80-16= 64
So Y eats 64 chocolates in 16 days.
Hence efficiency of Y is : 4 chocos / day
If they work together , Total Efficiency would be (2 chocos / day+4 chocos / day)= 6 chocos / day
No of days they take together to finish 80 chocolates : (80/6)
:13 Days 8 Hours
Step-by-step explanation:
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