A can do a piece of work in 40 days. He works at it for 8 days and then B finishes the
remaining work in 16 days. How long will they take to complete the work if they do
and then B left the work.
it together?
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Answer : 1/15
Explanation :
A can do a piece of work in 40 days
Work of A in 1 day=1/40
Work of A in 5 days=5/40=1/8
1/8th part of work is done by A
Remaining work (1-1/8) = 7/8
7/8th part is done by B in 21 days
Total work will be done by B in = 21/7/8 = 21/7 × 8 =
24 days.
Work done by B in one day=1/24
Work done by A and B together in one day will be
(1/40 + 1/24)
(3+5/120) = 8/120 = 1/15.
A and B will take 15 days to complete the work together.
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