A can do a piece of work in 40 days. he works at it for 8 days and then B finishes the remaining work in 16 days. how long will they take to complete the work if they do it together?
Answers
Answer:
A csn do a piece of work in 40 days
Work of A in 1 day=1/40
Work of A in 5 days=5/40=1/8
1/8th part of work is done by A
Remaining work=(1−
8
1
)=
8
7
7/8th part is done by B in 21 days
Total work will be done by B in =
8
7
21
=
7
21
×8=24days
Work done by B in one day=1/24
Work done by A and B together in one day will be(
40
1
+
24
1
)
(
120
3+5
)=
120
8
=
15
1
A and B will take 15 days to complete the work together.
Step-by-step explanation:
No of days taken by CAN to finish the work= 40
So part of work done by CAN in 1 day= 1/40
Part of work done by CAN in 8 days= 8/40 = 1/5
The remaining part = 1 - 1/5 = 4/5
No of days taken by B to finish 4/5 part = 16
Part of work done by B in 1 day = (4/5)/16
=(4/5)(1/16)= 1/20
Part of work done by both together in 1 day = (1/40)+(1/20)= 3/40
So number of days taken both together to finish the work = 1 / (3/40) 40/3 = 16 2/3 days.