A can do a piece of work in 40 days. He works for 8 days and then B finishes the remaining work in 16 days. How long will they take to complete the work if they do it together?
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Given that A can do a piece of work in 40 days. But He works for 8 days.
Work was done by in 1-day = 1/40.
In that 8 days, Work done by A = (1/40 * 8)
= 1/5.
Given that B finishes the remaining work in 16 days.
The remaining work by b = 1 - 1/5
= 4/5.
B will complete total Work in = (16 * 5/4)
= 20 days.
Work was done by B in 1-day = 1/20.
(A+B)'s 1 -day work = 1/40 + 1/20
= 3/40.
If they work together they can finish the work in 40/3 days (or) 13 1/3 days.
Hope this helps!
Work was done by in 1-day = 1/40.
In that 8 days, Work done by A = (1/40 * 8)
= 1/5.
Given that B finishes the remaining work in 16 days.
The remaining work by b = 1 - 1/5
= 4/5.
B will complete total Work in = (16 * 5/4)
= 20 days.
Work was done by B in 1-day = 1/20.
(A+B)'s 1 -day work = 1/40 + 1/20
= 3/40.
If they work together they can finish the work in 40/3 days (or) 13 1/3 days.
Hope this helps!
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