Question

A can do a piece of work in 45 days.He works for 30 days and leaves.If B completes the remaining work in 5 days then in how many days can B alone complete the entire work.
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Answer 1

Answer:

$\pink{ \boxed{ \large{15 \: days}}}$

Step-by-step explanation:

$\red{ \mathfrak{ \large{Given}}}$

• A can do a piece of work in 45 days.
• He works for 30 days and leaves.
• B completes the remaining work in 5 days.

$\mathfrak{ \underline{ \underline{ \large{To \: find}}}}$

• The days B can alone do

$\pink{ \mathfrak{ \underbrace{Solution}}}$

As, A can do 1(whole) work in 45 days,

Then,

A's 1 day work is 1/45

A's 30 day work is 30/45 = 2/3

Rest of work is (1-2/3) = 1/3

According to the question,

B does 1/3 work in 5 days.

Then,

B does 1 (whole) work in

$= \frac{ 5 }{ \frac{1}{3} } \\ = 5 \times 3 \\ = 15$

Hence, B does alone can complete the work in 15 days.

❣Hope this helps you✌