Question

. A can do a piece of work in 6 days and B alone can do the same work in 12 days. Both of them working together will finish it in ​

Answer 1

Answer:

Here's how I see this problem.

If A can complete the work in 6 days, how much of the work does it complete in one day?

1/6 of the work. And if B completes the work in 12 days, it completes 1/12 of the work in one day. Finding a common denominator 1/6 = 2/12

Thus, working side by side, both machines, or whatever they are, combine to complete: (2/12) + (1/12) = 3/12 of the work. 3/12 simplifies to 1/4, this means one quarter of the job is completed in one day. Therfore, the work is completed in four days.

Step-by-step explanation:

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